Base | Representation |
---|---|
bin | 11001101100100001111111… |
… | …001011010001110101100001 |
3 | 112211010202221201111220021200 |
4 | 121230201333023101311201 |
5 | 104303034132131433200 |
6 | 1040204402555311413 |
7 | 32542540456150236 |
oct | 3154417713216541 |
9 | 484122851456250 |
10 | 113011313155425 |
11 | 33010913093aa3 |
12 | 1081242414b569 |
13 | 4b09bc8881669 |
14 | 1dc9ac354378d |
15 | d0ea3c252800 |
hex | 66c87f2d1d61 |
113011313155425 has 72 divisors (see below), whose sum is σ = 203915383546680. Its totient is φ = 59826275097600.
The previous prime is 113011313155399. The next prime is 113011313155441. The reversal of 113011313155425 is 524551313110311.
113011313155425 is a `hidden beast` number, since 1 + 1 + 30 + 11 + 31 + 31 + 554 + 2 + 5 = 666.
It can be written as a sum of positive squares in 12 ways, for example, as 3272640849 + 113008040514576 = 57207^2 + 10630524^2 .
It is not a de Polignac number, because 113011313155425 - 212 = 113011313151329 is a prime.
It is a super-2 number, since 2×1130113131554252 (a number of 29 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 113011313155425.
It is an unprimeable number.
It is a polite number, since it can be written in 71 ways as a sum of consecutive naturals, for example, 291441571 + ... + 291829079.
It is an arithmetic number, because the mean of its divisors is an integer number (2832158104815).
Almost surely, 2113011313155425 is an apocalyptic number.
113011313155425 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
It is an amenable number.
113011313155425 is a deficient number, since it is larger than the sum of its proper divisors (90904070391255).
113011313155425 is a wasteful number, since it uses less digits than its factorization.
113011313155425 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 397123 (or 397115 counting only the distinct ones).
The product of its (nonzero) digits is 27000, while the sum is 36.
Adding to 113011313155425 its reverse (524551313110311), we get a palindrome (637562626265736).
The spelling of 113011313155425 in words is "one hundred thirteen trillion, eleven billion, three hundred thirteen million, one hundred fifty-five thousand, four hundred twenty-five".
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