113011320202020 has 288 divisors, whose sum is σ = 359493956142048. Its totient is φ = 28709073616896.

The previous prime is 113011320202009. The next prime is 113011320202063. The reversal of 113011320202020 is 20202023110311.

113011320202020 is a `hidden beast` number, since 1 + 1 + 301 + 1 + 320 + 2 + 0 + 20 + 20 = 666.

It can be written as a sum of positive squares in 16 ways, for example, as 3836364664896 + 109174955537124 = 1958664^2 + 10448682^2 .

It is a super-2 number, since 2×113011320202020² (a number of 29 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (18).

It is a junction number, because it is equal to n+sod(n) for n = 113011320201984 and 113011320202002.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 95 ways as a sum of consecutive naturals, for example, 65758312 + ... + 67455008.

It is an arithmetic number, because the mean of its divisors is an integer number (1248242903271).

Almost surely, 2^{113011320202020} is an apocalyptic number.

113011320202020 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 113011320202020, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (179746978071024).

113011320202020 is an abundant number, since it is smaller than the sum of its proper divisors (246482635940028).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

113011320202020 is a wasteful number, since it uses less digits than its factorization.

113011320202020 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1696959 (or 1696954 counting only the distinct ones).

The product of its (nonzero) digits is 144, while the sum is 18.

Adding to 113011320202020 its reverse (20202023110311), we get a palindrome (133213343312331).

The spelling of 113011320202020 in words is "one hundred thirteen trillion, eleven billion, three hundred twenty million, two hundred two thousand, twenty".