Base | Representation |
---|---|
bin | 10000011100100000000… |
… | …000001100111111111010 |
3 | 11000001000112121002001002 |
4 | 100130200000030333322 |
5 | 122003433002314002 |
6 | 2223100014325002 |
7 | 144435155515106 |
oct | 20344000147772 |
9 | 4001015532032 |
10 | 1130113323002 |
11 | 3a63075662a4 |
12 | 1630347b9762 |
13 | 8275279a0b1 |
14 | 3c9aa9b0906 |
15 | 1e5e4512002 |
hex | 1072000cffa |
1130113323002 has 4 divisors (see below), whose sum is σ = 1695169984506. Its totient is φ = 565056661500.
The previous prime is 1130113322983. The next prime is 1130113323013. The reversal of 1130113323002 is 2003233110311.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 620504373841 + 509608949161 = 787721^2 + 713869^2 .
It is a super-2 number, since 2×11301133230022 (a number of 25 digits) contains 22 as substring.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 282528330749 + ... + 282528330752.
Almost surely, 21130113323002 is an apocalyptic number.
1130113323002 is a deficient number, since it is larger than the sum of its proper divisors (565056661504).
1130113323002 is an equidigital number, since it uses as much as digits as its factorization.
1130113323002 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 565056661503.
The product of its (nonzero) digits is 324, while the sum is 20.
Adding to 1130113323002 its reverse (2003233110311), we get a palindrome (3133346433313).
The spelling of 1130113323002 in words is "one trillion, one hundred thirty billion, one hundred thirteen million, three hundred twenty-three thousand, two".
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