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11301312220133 = 13869331709241
BaseRepresentation
bin1010010001110100101010…
…1100110100101111100101
31111000101122212202101200012
42210131022230310233211
52440130041412021013
640011430130100005
72244331023613445
oct244351254645745
944011585671605
1011301312220133
11366795013a661
12132632a71a605
1363c92b078b80
142b0db4a9a125
15148e8e16e1a8
hexa474ab34be5

11301312220133 has 4 divisors (see below), whose sum is σ = 12170643929388. Its totient is φ = 10431980510880.

The previous prime is 11301312220127. The next prime is 11301312220157. The reversal of 11301312220133 is 33102221310311.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 6084939432289 + 5216372787844 = 2466767^2 + 2283938^2 .

It is a cyclic number.

It is not a de Polignac number, because 11301312220133 - 24 = 11301312220117 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 11301312220099 and 11301312220108.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11301312220123) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 434665854608 + ... + 434665854633.

It is an arithmetic number, because the mean of its divisors is an integer number (3042660982347).

Almost surely, 211301312220133 is an apocalyptic number.

11301312220133 is a gapful number since it is divisible by the number (13) formed by its first and last digit.

It is an amenable number.

11301312220133 is a deficient number, since it is larger than the sum of its proper divisors (869331709255).

11301312220133 is an equidigital number, since it uses as much as digits as its factorization.

11301312220133 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 869331709254.

The product of its (nonzero) digits is 648, while the sum is 23.

Adding to 11301312220133 its reverse (33102221310311), we get a palindrome (44403533530444).

The spelling of 11301312220133 in words is "eleven trillion, three hundred one billion, three hundred twelve million, two hundred twenty thousand, one hundred thirty-three".

Divisors: 1 13 869331709241 11301312220133