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1130132013133 = 8313616048351
BaseRepresentation
bin10000011100100001000…
…111100000000001001101
311000001001211202122002011
4100130201013200001031
5122004002243410013
62223101523101221
7144435503420224
oct20344107400115
94001054678064
101130132013133
113a6317071492
1216303ab11811
1382756612246
143c9ad277cbb
151e5e5ea4c3d
hex107211e004d

1130132013133 has 4 divisors (see below), whose sum is σ = 1143748061568. Its totient is φ = 1116515964700.

The previous prime is 1130132013113. The next prime is 1130132013181. The reversal of 1130132013133 is 3313102310311.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1130132013133 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1130132013113) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6808024093 + ... + 6808024258.

It is an arithmetic number, because the mean of its divisors is an integer number (285937015392).

Almost surely, 21130132013133 is an apocalyptic number.

It is an amenable number.

1130132013133 is a deficient number, since it is larger than the sum of its proper divisors (13616048435).

1130132013133 is an equidigital number, since it uses as much as digits as its factorization.

1130132013133 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 13616048434.

The product of its (nonzero) digits is 486, while the sum is 22.

Adding to 1130132013133 its reverse (3313102310311), we get a palindrome (4443234323444).

The spelling of 1130132013133 in words is "one trillion, one hundred thirty billion, one hundred thirty-two million, thirteen thousand, one hundred thirty-three".

Divisors: 1 83 13616048351 1130132013133