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1130200002001 = 7161457143143
BaseRepresentation
bin10000011100100101001…
…010110110110111010001
311000001020120200211021101
4100130211022312313101
5122004122200031001
62223112352224401
7144440260336420
oct20344512666721
94001216624241
101130200002001
113a6351489534
1216305983b101
1382767728545
143c9b82d52b7
151e5ebe34a01
hex107252b6dd1

1130200002001 has 4 divisors (see below), whose sum is σ = 1291657145152. Its totient is φ = 968742858852.

The previous prime is 1130200001971. The next prime is 1130200002007. The reversal of 1130200002001 is 1002000020311.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1130200002001 - 227 = 1130065784273 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1130200002007) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 80728571565 + ... + 80728571578.

It is an arithmetic number, because the mean of its divisors is an integer number (322914286288).

Almost surely, 21130200002001 is an apocalyptic number.

It is an amenable number.

1130200002001 is a deficient number, since it is larger than the sum of its proper divisors (161457143151).

1130200002001 is an equidigital number, since it uses as much as digits as its factorization.

1130200002001 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 161457143150.

The product of its (nonzero) digits is 12, while the sum is 10.

Adding to 1130200002001 its reverse (1002000020311), we get a palindrome (2132200022312).

The spelling of 1130200002001 in words is "one trillion, one hundred thirty billion, two hundred million, two thousand, one".

Divisors: 1 7 161457143143 1130200002001