Base | Representation |
---|---|
bin | 1010010001110111010001… |
… | …1010010111000101001001 |
3 | 1111000110110122120001220002 |
4 | 2210131310122113011021 |
5 | 2440133010034214423 |
6 | 40012023405212345 |
7 | 2244354252054410 |
oct | 244356432270511 |
9 | 44013418501802 |
10 | 11302012023113 |
11 | 366817a164a29 |
12 | 13264a4b610b5 |
13 | 63ca10049686 |
14 | 2b103d9c2477 |
15 | 148ed0803228 |
hex | a4774697149 |
11302012023113 has 4 divisors (see below), whose sum is σ = 12916585169280. Its totient is φ = 9687438876948.
The previous prime is 11302012023089. The next prime is 11302012023143. The reversal of 11302012023113 is 31132021020311.
It is a happy number.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is not a de Polignac number, because 11302012023113 - 28 = 11302012022857 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (11302012023143) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 807286573073 + ... + 807286573086.
It is an arithmetic number, because the mean of its divisors is an integer number (3229146292320).
Almost surely, 211302012023113 is an apocalyptic number.
It is an amenable number.
11302012023113 is a deficient number, since it is larger than the sum of its proper divisors (1614573146167).
11302012023113 is an equidigital number, since it uses as much as digits as its factorization.
11302012023113 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1614573146166.
The product of its (nonzero) digits is 216, while the sum is 20.
Adding to 11302012023113 its reverse (31132021020311), we get a palindrome (42434033043424).
The spelling of 11302012023113 in words is "eleven trillion, three hundred two billion, twelve million, twenty-three thousand, one hundred thirteen".
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