1130201301311 has 4 divisors (see below), whose sum is σ = 1145683510992. Its totient is φ = 1114719091632.

The previous prime is 1130201301263. The next prime is 1130201301349. The reversal of 1130201301311 is 1131031020311.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1130201301311 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 1130201301311.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1130201301371) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 7741104731 + ... + 7741104876.

It is an arithmetic number, because the mean of its divisors is an integer number (286420877748).

Almost surely, 2^{1130201301311} is an apocalyptic number.

1130201301311 is a deficient number, since it is larger than the sum of its proper divisors (15482209681).

1130201301311 is an equidigital number, since it uses as much as digits as its factorization.

1130201301311 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 15482209680.

The product of its (nonzero) digits is 54, while the sum is 17.

Adding to 1130201301311 its reverse (1131031020311), we get a palindrome (2261232321622).

The spelling of 1130201301311 in words is "one trillion, one hundred thirty billion, two hundred one million, three hundred one thousand, three hundred eleven".