1130204330001 has 12 divisors (see below), whose sum is σ = 1676639457012. Its totient is φ = 733105511136.

The previous prime is 1130204329973. The next prime is 1130204330023. The reversal of 1130204330001 is 1000334020311.

1130204330001 is a `hidden beast` number, since 1 + 130 + 204 + 330 + 0 + 0 + 1 = 666.

It can be written as a sum of positive squares in 2 ways, for example, as 923374933776 + 206829396225 = 960924^2 + 454785^2 .

It is not a de Polignac number, because 1130204330001 - 2³¹ = 1128056846353 is a prime.

It is not an unprimeable number, because it can be changed into a prime (1130204330041) by changing a digit.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 1697003166 + ... + 1697003831.

It is an arithmetic number, because the mean of its divisors is an integer number (139719954751).

Almost surely, 2^{1130204330001} is an apocalyptic number.

It is an amenable number.

1130204330001 is a deficient number, since it is larger than the sum of its proper divisors (546435127011).

1130204330001 is a wasteful number, since it uses less digits than its factorization.

1130204330001 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3394007040 (or 3394007037 counting only the distinct ones).

The product of its (nonzero) digits is 216, while the sum is 18.

Adding to 1130204330001 its reverse (1000334020311), we get a palindrome (2130538350312).

The spelling of 1130204330001 in words is "one trillion, one hundred thirty billion, two hundred four million, three hundred thirty thousand, one".