Base | Representation |
---|---|
bin | 10000011100100101011… |
… | …011010111100000111001 |
3 | 11000001020212211201020011 |
4 | 100130211123113200321 |
5 | 122004124302030131 |
6 | 2223113025101521 |
7 | 144440342203543 |
oct | 20344533274071 |
9 | 4001225751204 |
10 | 1130204330041 |
11 | 3a6353975226 |
12 | 16305b1878a1 |
13 | 827685b2507 |
14 | 3c9b8b00693 |
15 | 1e5ec4dc0b1 |
hex | 107256d7839 |
1130204330041 has 2 divisors, whose sum is σ = 1130204330042. Its totient is φ = 1130204330040.
The previous prime is 1130204330027. The next prime is 1130204330051. The reversal of 1130204330041 is 1400334020311.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 923961190441 + 206243139600 = 961229^2 + 454140^2 .
It is a cyclic number.
It is not a de Polignac number, because 1130204330041 - 27 = 1130204329913 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1130204329994 and 1130204330021.
It is not a weakly prime, because it can be changed into another prime (1130204330051) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 565102165020 + 565102165021.
It is an arithmetic number, because the mean of its divisors is an integer number (565102165021).
Almost surely, 21130204330041 is an apocalyptic number.
It is an amenable number.
1130204330041 is a deficient number, since it is larger than the sum of its proper divisors (1).
1130204330041 is an equidigital number, since it uses as much as digits as its factorization.
1130204330041 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 864, while the sum is 22.
Adding to 1130204330041 its reverse (1400334020311), we get a palindrome (2530538350352).
The spelling of 1130204330041 in words is "one trillion, one hundred thirty billion, two hundred four million, three hundred thirty thousand, forty-one".
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