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11302043310101 = 50975072957827
BaseRepresentation
bin1010010001110111011001…
…0001101101100000010101
31111000110112211102121120102
42210131312101231200111
52440133041041410401
640012030443543445
72244355112023205
oct244356621554025
944013484377512
1011302043310101
113668195894345
1213264b352ab85
1363ca1668239b
142b1043c08405
15148ed343356b
hexa477646d815

11302043310101 has 8 divisors (see below), whose sum is σ = 11325760038240. Its totient is φ = 11278332513648.

The previous prime is 11302043310067. The next prime is 11302043310127. The reversal of 11302043310101 is 10101334020311.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-11302043310101 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11302043312101) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2342150 + ... + 5299976.

It is an arithmetic number, because the mean of its divisors is an integer number (1415720004780).

Almost surely, 211302043310101 is an apocalyptic number.

It is an amenable number.

11302043310101 is a deficient number, since it is larger than the sum of its proper divisors (23716728139).

11302043310101 is an equidigital number, since it uses as much as digits as its factorization.

11302043310101 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2965843.

The product of its (nonzero) digits is 216, while the sum is 20.

Adding to 11302043310101 its reverse (10101334020311), we get a palindrome (21403377330412).

The spelling of 11302043310101 in words is "eleven trillion, three hundred two billion, forty-three million, three hundred ten thousand, one hundred one".

Divisors: 1 509 7507 2957827 3821063 1505533943 22204407289 11302043310101