113020434320251 has 4 divisors (see below), whose sum is σ = 113020458512112. Its totient is φ = 113020410128392.

The previous prime is 113020434320237. The next prime is 113020434320257. The reversal of 113020434320251 is 152023434020311.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 113020434320251 - 2⁵ = 113020434320219 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (113020434320257) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2606800 + ... + 15258973.

It is an arithmetic number, because the mean of its divisors is an integer number (28255114628028).

Almost surely, 2^{113020434320251} is an apocalyptic number.

113020434320251 is a deficient number, since it is larger than the sum of its proper divisors (24191861).

113020434320251 is an equidigital number, since it uses as much as digits as its factorization.

113020434320251 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 24191860.

The product of its (nonzero) digits is 17280, while the sum is 31.

Adding to 113020434320251 its reverse (152023434020311), we get a palindrome (265043868340562).

The spelling of 113020434320251 in words is "one hundred thirteen trillion, twenty billion, four hundred thirty-four million, three hundred twenty thousand, two hundred fifty-one".