113020434320237 has 2 divisors, whose sum is σ = 113020434320238. Its totient is φ = 113020434320236.

The previous prime is 113020434320219. The next prime is 113020434320257. The reversal of 113020434320237 is 732023434020311.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 93867303528196 + 19153130792041 = 9688514^2 + 4376429^2 .

It is an emirp because it is prime and its reverse (732023434020311) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 113020434320237 - 2⁶ = 113020434320173 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 113020434320197 and 113020434320206.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (113020434320207) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56510217160118 + 56510217160119.

It is an arithmetic number, because the mean of its divisors is an integer number (56510217160119).

Almost surely, 2^{113020434320237} is an apocalyptic number.

It is an amenable number.

113020434320237 is a deficient number, since it is larger than the sum of its proper divisors (1).

113020434320237 is an equidigital number, since it uses as much as digits as its factorization.

113020434320237 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 72576, while the sum is 35.

Adding to 113020434320237 its reverse (732023434020311), we get a palindrome (845043868340548).

The spelling of 113020434320237 in words is "one hundred thirteen trillion, twenty billion, four hundred thirty-four million, three hundred twenty thousand, two hundred thirty-seven".