1130212332131 has 4 divisors (see below), whose sum is σ = 1169185171200. Its totient is φ = 1091239493064.

The previous prime is 1130212332113. The next prime is 1130212332133. The reversal of 1130212332131 is 1312332120311.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1130212332131 - 2¹⁰ = 1130212331107 is a prime.

It is a super-2 number, since 2×1130212332131² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1130212332097 and 1130212332106.

It is not an unprimeable number, because it can be changed into a prime (1130212332133) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 19486419491 + ... + 19486419548.

It is an arithmetic number, because the mean of its divisors is an integer number (292296292800).

Almost surely, 2^{1130212332131} is an apocalyptic number.

1130212332131 is a deficient number, since it is larger than the sum of its proper divisors (38972839069).

1130212332131 is an equidigital number, since it uses as much as digits as its factorization.

1130212332131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 38972839068.

The product of its (nonzero) digits is 648, while the sum is 23.

Adding to 1130212332131 its reverse (1312332120311), we get a palindrome (2442544452442).

The spelling of 1130212332131 in words is "one trillion, one hundred thirty billion, two hundred twelve million, three hundred thirty-two thousand, one hundred thirty-one".