Base | Representation |
---|---|
bin | 10011000110001101000… |
… | …101110000000011110111 |
3 | 11122110100200102001222212 |
4 | 103012031011300003313 |
5 | 133000124010322221 |
6 | 2442513235444035 |
7 | 163545545654042 |
oct | 23061505600367 |
9 | 4573320361885 |
10 | 1312332120311 |
11 | 4666142a6763 |
12 | 19240945661b |
13 | 969a1cc4b54 |
14 | 4773533bc59 |
15 | 2420b8ebb5b |
hex | 1318d1700f7 |
1312332120311 has 2 divisors, whose sum is σ = 1312332120312. Its totient is φ = 1312332120310.
The previous prime is 1312332120283. The next prime is 1312332120313. The reversal of 1312332120311 is 1130212332131.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1312332120311 - 26 = 1312332120247 is a prime.
Together with 1312332120313, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1312332120313) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 656166060155 + 656166060156.
It is an arithmetic number, because the mean of its divisors is an integer number (656166060156).
Almost surely, 21312332120311 is an apocalyptic number.
1312332120311 is a deficient number, since it is larger than the sum of its proper divisors (1).
1312332120311 is an equidigital number, since it uses as much as digits as its factorization.
1312332120311 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 648, while the sum is 23.
Adding to 1312332120311 its reverse (1130212332131), we get a palindrome (2442544452442).
The spelling of 1312332120311 in words is "one trillion, three hundred twelve billion, three hundred thirty-two million, one hundred twenty thousand, three hundred eleven".
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