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1130220143 = 13811107201
BaseRepresentation
bin100001101011101…
…1100101001101111
32220202201010120022
41003113130221233
54303314021033
6304052312355
740002466313
oct10327345157
92822633508
101130220143
1152aa86138
122766126bb
13150201c20
14aa167b43
1569355098
hex435dca6f

1130220143 has 8 divisors (see below), whose sum is σ = 1218672336. Its totient is φ = 1041984000.

The previous prime is 1130220089. The next prime is 1130220181. The reversal of 1130220143 is 3410220311.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 1130220143 - 26 = 1130220079 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1130220043) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 43058 + ... + 64143.

It is an arithmetic number, because the mean of its divisors is an integer number (152334042).

Almost surely, 21130220143 is an apocalyptic number.

1130220143 is a gapful number since it is divisible by the number (13) formed by its first and last digit.

1130220143 is a deficient number, since it is larger than the sum of its proper divisors (88452193).

1130220143 is a wasteful number, since it uses less digits than its factorization.

1130220143 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 108025.

The product of its (nonzero) digits is 144, while the sum is 17.

The square root of 1130220143 is about 33618.7468981222. The cubic root of 1130220143 is about 1041.6480720421.

Adding to 1130220143 its reverse (3410220311), we get a palindrome (4540440454).

The spelling of 1130220143 in words is "one billion, one hundred thirty million, two hundred twenty thousand, one hundred forty-three".

Divisors: 1 13 811 10543 107201 1393613 86940011 1130220143