113023120122013 has 4 divisors (see below), whose sum is σ = 113034640172608. Its totient is φ = 113011600071420.

The previous prime is 113023120121981. The next prime is 113023120122023. The reversal of 113023120122013 is 310221021320311.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 113023120122013 - 2⁵ = 113023120121981 is a prime.

It is a super-2 number, since 2×113023120122013² (a number of 29 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (113023120122023) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5760010581 + ... + 5760030202.

It is an arithmetic number, because the mean of its divisors is an integer number (28258660043152).

Almost surely, 2^{113023120122013} is an apocalyptic number.

It is an amenable number.

113023120122013 is a deficient number, since it is larger than the sum of its proper divisors (11520050595).

113023120122013 is an equidigital number, since it uses as much as digits as its factorization.

113023120122013 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 11520050594.

The product of its (nonzero) digits is 432, while the sum is 22.

Adding to 113023120122013 its reverse (310221021320311), we get a palindrome (423244141442324).

The spelling of 113023120122013 in words is "one hundred thirteen trillion, twenty-three billion, one hundred twenty million, one hundred twenty-two thousand, thirteen".