1130231411433 has 48 divisors (see below), whose sum is σ = 1689005260800. Its totient is φ = 727858666080.

The previous prime is 1130231411417. The next prime is 1130231411461. The reversal of 1130231411433 is 3341141320311.

1130231411433 is a `hidden beast` number, since 1 + 1 + 302 + 314 + 1 + 1 + 43 + 3 = 666.

It is not a de Polignac number, because 1130231411433 - 2⁴ = 1130231411417 is a prime.

It is a super-3 number, since 3×1130231411433³ (a number of 37 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a junction number, because it is equal to n+sod(n) for n = 1130231411397 and 1130231411406.

It is not an unprimeable number, because it can be changed into a prime (1130231411233) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 142720048 + ... + 142727966.

It is an arithmetic number, because the mean of its divisors is an integer number (35187609600).

Almost surely, 2^{1130231411433} is an apocalyptic number.

It is an amenable number.

1130231411433 is a deficient number, since it is larger than the sum of its proper divisors (558773849367).

1130231411433 is a wasteful number, since it uses less digits than its factorization.

1130231411433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 12322 (or 12319 counting only the distinct ones).

The product of its (nonzero) digits is 2592, while the sum is 27.

Adding to 1130231411433 its reverse (3341141320311), we get a palindrome (4471372731744).

The spelling of 1130231411433 in words is "one trillion, one hundred thirty billion, two hundred thirty-one million, four hundred eleven thousand, four hundred thirty-three".