Base | Representation |
---|---|
bin | 10000011100101011001… |
… | …101010100010010001111 |
3 | 11000001111122022210212000 |
4 | 100130223031110102033 |
5 | 122004324113410340 |
6 | 2223130411443343 |
7 | 144442630420326 |
oct | 20345315242217 |
9 | 4001448283760 |
10 | 1130301310095 |
11 | 3a63a3693831 |
12 | 163087756553 |
13 | 82782709569 |
14 | 3c9c79470bd |
15 | 1e605c96d30 |
hex | 1072b35448f |
1130301310095 has 16 divisors (see below), whose sum is σ = 2009424551520. Its totient is φ = 602827365312.
The previous prime is 1130301310063. The next prime is 1130301310111. The reversal of 1130301310095 is 5900131030311.
1130301310095 is a `hidden beast` number, since 11 + 30 + 301 + 310 + 0 + 9 + 5 = 666.
It is not a de Polignac number, because 1130301310095 - 25 = 1130301310063 is a prime.
It is a Harshad number since it is a multiple of its sum of digits (27).
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 4186301014 + ... + 4186301283.
It is an arithmetic number, because the mean of its divisors is an integer number (125589034470).
Almost surely, 21130301310095 is an apocalyptic number.
1130301310095 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
1130301310095 is a deficient number, since it is larger than the sum of its proper divisors (879123241425).
1130301310095 is an equidigital number, since it uses as much as digits as its factorization.
1130301310095 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 8372602311 (or 8372602305 counting only the distinct ones).
The product of its (nonzero) digits is 1215, while the sum is 27.
The spelling of 1130301310095 in words is "one trillion, one hundred thirty billion, three hundred one million, three hundred ten thousand, ninety-five".
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