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113030210132122 = 256515105066061
BaseRepresentation
bin11001101100110011100101…
…100001100001100010011010
3112211012120201200111210000111
4121230303211201201202122
5104303341332243211442
61040221210043154534
732544106655616613
oct3154634541414232
9484176650453014
10113030210132122
113301892aa23308
1210816018815a4a
134b0b91a88a48a
141dca997140c0a
15d1029623bb17
hex66cce586189a

113030210132122 has 4 divisors (see below), whose sum is σ = 169545315198186. Its totient is φ = 56515105066060.

The previous prime is 113030210132117. The next prime is 113030210132129. The reversal of 113030210132122 is 221231012030311.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 110631921185241 + 2398288946881 = 10518171^2 + 1548641^2 .

It is a junction number, because it is equal to n+sod(n) for n = 113030210132093 and 113030210132102.

It is not an unprimeable number, because it can be changed into a prime (113030210132129) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 28257552533029 + ... + 28257552533032.

Almost surely, 2113030210132122 is an apocalyptic number.

113030210132122 is a deficient number, since it is larger than the sum of its proper divisors (56515105066064).

113030210132122 is an equidigital number, since it uses as much as digits as its factorization.

113030210132122 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 56515105066063.

The product of its (nonzero) digits is 432, while the sum is 22.

Adding to 113030210132122 its reverse (221231012030311), we get a palindrome (334261222162433).

The spelling of 113030210132122 in words is "one hundred thirteen trillion, thirty billion, two hundred ten million, one hundred thirty-two thousand, one hundred twenty-two".

Divisors: 1 2 56515105066061 113030210132122