Base | Representation |
---|---|
bin | 11001101100110011100101… |
… | …100001100001100010011010 |
3 | 112211012120201200111210000111 |
4 | 121230303211201201202122 |
5 | 104303341332243211442 |
6 | 1040221210043154534 |
7 | 32544106655616613 |
oct | 3154634541414232 |
9 | 484176650453014 |
10 | 113030210132122 |
11 | 3301892aa23308 |
12 | 10816018815a4a |
13 | 4b0b91a88a48a |
14 | 1dca997140c0a |
15 | d1029623bb17 |
hex | 66cce586189a |
113030210132122 has 4 divisors (see below), whose sum is σ = 169545315198186. Its totient is φ = 56515105066060.
The previous prime is 113030210132117. The next prime is 113030210132129. The reversal of 113030210132122 is 221231012030311.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 110631921185241 + 2398288946881 = 10518171^2 + 1548641^2 .
It is a junction number, because it is equal to n+sod(n) for n = 113030210132093 and 113030210132102.
It is not an unprimeable number, because it can be changed into a prime (113030210132129) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 28257552533029 + ... + 28257552533032.
Almost surely, 2113030210132122 is an apocalyptic number.
113030210132122 is a deficient number, since it is larger than the sum of its proper divisors (56515105066064).
113030210132122 is an equidigital number, since it uses as much as digits as its factorization.
113030210132122 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 56515105066063.
The product of its (nonzero) digits is 432, while the sum is 22.
Adding to 113030210132122 its reverse (221231012030311), we get a palindrome (334261222162433).
The spelling of 113030210132122 in words is "one hundred thirteen trillion, thirty billion, two hundred ten million, one hundred thirty-two thousand, one hundred twenty-two".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.075 sec. • engine limits •