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1130302232101 = 7161471747443
BaseRepresentation
bin10000011100101011010…
…000110101011000100101
311000001111201001122121101
4100130223100311120211
5122004324332411401
62223130443320101
7144442641310360
oct20345320653045
94001451048541
101130302232101
113a63a4163519
12163087b20031
1382782970123
143c9c7b070d7
151e605dca101
hex1072b435625

1130302232101 has 4 divisors (see below), whose sum is σ = 1291773979552. Its totient is φ = 968830484652.

The previous prime is 1130302232083. The next prime is 1130302232197. The reversal of 1130302232101 is 1012322030311.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1130302232101 - 25 = 1130302232069 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1130302232701) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 80735873715 + ... + 80735873728.

It is an arithmetic number, because the mean of its divisors is an integer number (322943494888).

Almost surely, 21130302232101 is an apocalyptic number.

It is an amenable number.

1130302232101 is a deficient number, since it is larger than the sum of its proper divisors (161471747451).

1130302232101 is an equidigital number, since it uses as much as digits as its factorization.

1130302232101 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 161471747450.

The product of its (nonzero) digits is 216, while the sum is 19.

Adding to 1130302232101 its reverse (1012322030311), we get a palindrome (2142624262412).

The spelling of 1130302232101 in words is "one trillion, one hundred thirty billion, three hundred two million, two hundred thirty-two thousand, one hundred one".

Divisors: 1 7 161471747443 1130302232101