11303100000001 has 4 divisors (see below), whose sum is σ = 11304440667904. Its totient is φ = 11301759332100.

The previous prime is 11303099999969. The next prime is 11303100000029. The reversal of 11303100000001 is 10000000130311.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 11303100000001 - 2⁵ = 11303099999969 is a prime.

It is a super-2 number, since 2×11303100000001² (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (11303100000041) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 670321305 + ... + 670338166.

It is an arithmetic number, because the mean of its divisors is an integer number (2826110166976).

Almost surely, 2^{11303100000001} is an apocalyptic number.

It is an amenable number.

11303100000001 is a deficient number, since it is larger than the sum of its proper divisors (1340667903).

11303100000001 is an equidigital number, since it uses as much as digits as its factorization.

11303100000001 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1340667902.

The product of its (nonzero) digits is 9, while the sum is 10.

Adding to 11303100000001 its reverse (10000000130311), we get a palindrome (21303100130312).

The spelling of 11303100000001 in words is "eleven trillion, three hundred three billion, one hundred million, one", and thus it is an aban number.