1130310031301 has 4 divisors (see below), whose sum is σ = 1233065488704. Its totient is φ = 1027554573900.

The previous prime is 1130310031261. The next prime is 1130310031339. The reversal of 1130310031301 is 1031300130311.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1130310031301 - 2³⁰ = 1129236289477 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 1130310031301.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1130310031351) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 51377728685 + ... + 51377728706.

It is an arithmetic number, because the mean of its divisors is an integer number (308266372176).

Almost surely, 2^{1130310031301} is an apocalyptic number.

1130310031301 is a gapful number since it is divisible by the number (11) formed by its first and last digit.

It is an amenable number.

1130310031301 is a deficient number, since it is larger than the sum of its proper divisors (102755457403).

1130310031301 is a wasteful number, since it uses less digits than its factorization.

1130310031301 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 102755457402.

The product of its (nonzero) digits is 81, while the sum is 17.

Adding to 1130310031301 its reverse (1031300130311), we get a palindrome (2161610161612).

The spelling of 1130310031301 in words is "one trillion, one hundred thirty billion, three hundred ten million, thirty-one thousand, three hundred one".