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1130311312130 = 25711133110313533
BaseRepresentation
bin10000011100101011110…
…011011110001100000010
311000001112100010222001202
4100130223303132030002
5122004334143442010
62223131410101202
7144443111425640
oct20345363361402
94001470128052
101130311312130
113a63a92a5480
1216308ab7a802
13827847cc020
143c9c8dcc190
151e606ac06a5
hex1072bcde302

1130311312130 has 256 divisors, whose sum is σ = 2823371292672. Its totient is φ = 314319744000.

The previous prime is 1130311312127. The next prime is 1130311312181. The reversal of 1130311312130 is 312131130311.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 127 ways as a sum of consecutive naturals, for example, 319927844 + ... + 319931376.

It is an arithmetic number, because the mean of its divisors is an integer number (11028794112).

Almost surely, 21130311312130 is an apocalyptic number.

1130311312130 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

1130311312130 is an abundant number, since it is smaller than the sum of its proper divisors (1693059980542).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1130311312130 is a wasteful number, since it uses less digits than its factorization.

1130311312130 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4633.

The product of its (nonzero) digits is 162, while the sum is 20.

Adding to 1130311312130 its reverse (312131130311), we get a palindrome (1442442442441).

It can be divided in two parts, 1130311 and 312130, that added together give a palindrome (1442441).

The spelling of 1130311312130 in words is "one trillion, one hundred thirty billion, three hundred eleven million, three hundred twelve thousand, one hundred thirty".