11303142433 has 8 divisors (see below), whose sum is σ = 12385023840. Its totient is φ = 10230314880.

The previous prime is 11303142397. The next prime is 11303142451. The reversal of 11303142433 is 33424130311.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 11303142433 - 2¹⁷ = 11303011361 is a prime.

It is a super-2 number, since 2×11303142433² (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 11303142398 and 11303142407.

It is not an unprimeable number, because it can be changed into a prime (11303142833) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2260848 + ... + 2265841.

It is an arithmetic number, because the mean of its divisors is an integer number (1548127980).

Almost surely, 2^11303142433 is an apocalyptic number.

It is an amenable number.

11303142433 is a deficient number, since it is larger than the sum of its proper divisors (1081881407).

11303142433 is a wasteful number, since it uses less digits than its factorization.

11303142433 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4526927.

The product of its (nonzero) digits is 2592, while the sum is 25.

Adding to 11303142433 its reverse (33424130311), we get a palindrome (44727272744).

The spelling of 11303142433 in words is "eleven billion, three hundred three million, one hundred forty-two thousand, four hundred thirty-three".