Base | Representation |
---|---|
bin | 10101000011011100… |
… | …10010010101111011 |
3 | 1002011201222001121121 |
4 | 22201232102111323 |
5 | 141122104400443 |
6 | 5105334450111 |
7 | 550050421135 |
oct | 124156222573 |
9 | 32151861547 |
10 | 11303200123 |
11 | 48803a8606 |
12 | 2235503937 |
13 | 10b19a5bc7 |
14 | 793278055 |
15 | 4624d14ed |
hex | 2a1b9257b |
11303200123 has 4 divisors (see below), whose sum is σ = 11304716920. Its totient is φ = 11301683328.
The previous prime is 11303200099. The next prime is 11303200127. The reversal of 11303200123 is 32100230311.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 32100230311 = 24107 ⋅1331573.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-11303200123 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 11303200097 and 11303200106.
It is not an unprimeable number, because it can be changed into a prime (11303200127) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 747165 + ... + 762142.
It is an arithmetic number, because the mean of its divisors is an integer number (2826179230).
Almost surely, 211303200123 is an apocalyptic number.
11303200123 is a deficient number, since it is larger than the sum of its proper divisors (1516797).
11303200123 is an equidigital number, since it uses as much as digits as its factorization.
11303200123 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1516796.
The product of its (nonzero) digits is 108, while the sum is 16.
Adding to 11303200123 its reverse (32100230311), we get a palindrome (43403430434).
The spelling of 11303200123 in words is "eleven billion, three hundred three million, two hundred thousand, one hundred twenty-three".
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