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11303200127 is a prime number
BaseRepresentation
bin10101000011011100…
…10010010101111111
31002011201222001121202
422201232102111333
5141122104401002
65105334450115
7550050421142
oct124156222577
932151861552
1011303200127
1148803a860a
12223550393b
1310b19a5bcb
14793278059
154624d1502
hex2a1b9257f

11303200127 has 2 divisors, whose sum is σ = 11303200128. Its totient is φ = 11303200126.

The previous prime is 11303200099. The next prime is 11303200133. The reversal of 11303200127 is 72100230311.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 11303200127 - 28 = 11303199871 is a prime.

It is a super-2 number, since 2×113032001272 (a number of 21 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 11303200099 and 11303200108.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11303200177) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5651600063 + 5651600064.

It is an arithmetic number, because the mean of its divisors is an integer number (5651600064).

Almost surely, 211303200127 is an apocalyptic number.

11303200127 is a deficient number, since it is larger than the sum of its proper divisors (1).

11303200127 is an equidigital number, since it uses as much as digits as its factorization.

11303200127 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 252, while the sum is 20.

Adding to 11303200127 its reverse (72100230311), we get a palindrome (83403430438).

The spelling of 11303200127 in words is "eleven billion, three hundred three million, two hundred thousand, one hundred twenty-seven".