11303400013 has 4 divisors (see below), whose sum is σ = 11303618400. Its totient is φ = 11303181628.

The previous prime is 11303399999. The next prime is 11303400019. The reversal of 11303400013 is 31000430311.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 31000430311 = 31 ⋅1000013881.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-11303400013 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 11303400013.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11303400019) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 17256 + ... + 151342.

It is an arithmetic number, because the mean of its divisors is an integer number (2825904600).

Almost surely, 2^11303400013 is an apocalyptic number.

It is an amenable number.

11303400013 is a deficient number, since it is larger than the sum of its proper divisors (218387).

11303400013 is an equidigital number, since it uses as much as digits as its factorization.

11303400013 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 218386.

The product of its (nonzero) digits is 108, while the sum is 16.

Adding to 11303400013 its reverse (31000430311), we get a palindrome (42303830324).

The spelling of 11303400013 in words is "eleven billion, three hundred three million, four hundred thousand, thirteen".