1130340031 has 4 divisors (see below), whose sum is σ = 1130407432. Its totient is φ = 1130272632.

The previous prime is 1130340019. The next prime is 1130340053. The reversal of 1130340031 is 1300430311.

It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length, and also an emirpimes, since its reverse is a distinct semiprime: 1300430311 = 103 ⋅12625537.

It is a cyclic number.

It is not a de Polignac number, because 1130340031 - 2⁵ = 1130339999 is a prime.

It is a super-2 number, since 2×1130340031² = 2555337171362161922, which contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1130339987 and 1130340014.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1130340131) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 13381 + ... + 49393.

It is an arithmetic number, because the mean of its divisors is an integer number (282601858).

Almost surely, 2^1130340031 is an apocalyptic number.

1130340031 is a deficient number, since it is larger than the sum of its proper divisors (67401).

1130340031 is an equidigital number, since it uses as much as digits as its factorization.

1130340031 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 67400.

The product of its (nonzero) digits is 108, while the sum is 16.

The square root of 1130340031 is about 33620.5299036169. The cubic root of 1130340031 is about 1041.6849016484.

Adding to 1130340031 its reverse (1300430311), we get a palindrome (2430770342).

The spelling of 1130340031 in words is "one billion, one hundred thirty million, three hundred forty thousand, thirty-one".