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1130354021215 = 5226070804243
BaseRepresentation
bin10000011100101110010…
…110011001001101011111
311000001122022111210220201
4100130232112121031133
5122004431112134330
62223135533324331
7144444140436136
oct20345626311537
94001568453821
101130354021215
113a6420416441
121630a13366a7
1382790603983
143c9d094891d
151e60a709eca
hex1072e59935f

1130354021215 has 4 divisors (see below), whose sum is σ = 1356424825464. Its totient is φ = 904283216968.

The previous prime is 1130354021189. The next prime is 1130354021231. The reversal of 1130354021215 is 5121204530311.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1130354021215 - 27 = 1130354021087 is a prime.

It is a Duffinian number.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 113035402117 + ... + 113035402126.

It is an arithmetic number, because the mean of its divisors is an integer number (339106206366).

Almost surely, 21130354021215 is an apocalyptic number.

1130354021215 is a deficient number, since it is larger than the sum of its proper divisors (226070804249).

1130354021215 is an equidigital number, since it uses as much as digits as its factorization.

1130354021215 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 226070804248.

The product of its (nonzero) digits is 3600, while the sum is 28.

Adding to 1130354021215 its reverse (5121204530311), we get a palindrome (6251558551526).

It can be divided in two parts, 113035 and 4021215, that added together give a triangular number (4134250 = T2875).

The spelling of 1130354021215 in words is "one trillion, one hundred thirty billion, three hundred fifty-four million, twenty-one thousand, two hundred fifteen".

Divisors: 1 5 226070804243 1130354021215