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11303540325 = 325271119231493
BaseRepresentation
bin10101000011011111…
…00101011001100101
31002011202121100021200
422201233211121211
5141122201242300
65105350033113
7550053336030
oct124157453145
932152540250
1011303540325
114880610170
122235648799
1310b1a949cc
14793326017
1546254c200
hex2a1be5665

11303540325 has 288 divisors, whose sum is σ = 27743938560. Its totient is φ = 4253990400.

The previous prime is 11303540321. The next prime is 11303540327. The reversal of 11303540325 is 52304530311.

11303540325 is a `hidden beast` number, since 113 + 0 + 3 + 540 + 3 + 2 + 5 = 666.

It is not a de Polignac number, because 11303540325 - 22 = 11303540321 is a prime.

It is a super-2 number, since 2×113035403252 (a number of 21 digits) contains 22 as substring.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11303540321) by changing a digit.

It is a polite number, since it can be written in 287 ways as a sum of consecutive naturals, for example, 7570279 + ... + 7571771.

It is an arithmetic number, because the mean of its divisors is an integer number (96333120).

Almost surely, 211303540325 is an apocalyptic number.

11303540325 is a gapful number since it is divisible by the number (15) formed by its first and last digit.

It is an amenable number.

11303540325 is an abundant number, since it is smaller than the sum of its proper divisors (16440398235).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

11303540325 is a wasteful number, since it uses less digits than its factorization.

11303540325 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1569 (or 1561 counting only the distinct ones).

The product of its (nonzero) digits is 5400, while the sum is 27.

The spelling of 11303540325 in words is "eleven billion, three hundred three million, five hundred forty thousand, three hundred twenty-five".