11304002341333 has 4 divisors (see below), whose sum is σ = 12173540982988. Its totient is φ = 10434463699680.

The previous prime is 11304002341321. The next prime is 11304002341409. The reversal of 11304002341333 is 33314320040311.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 5286955238244 + 6017047103089 = 2299338^2 + 2452967^2 .

It is a cyclic number.

It is not a de Polignac number, because 11304002341333 - 2⁵ = 11304002341301 is a prime.

It is a super-3 number, since 3×11304002341333³ (a number of 40 digits) contains 333 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11304002311333) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 434769320808 + ... + 434769320833.

It is an arithmetic number, because the mean of its divisors is an integer number (3043385245747).

Almost surely, 2^{11304002341333} is an apocalyptic number.

11304002341333 is a gapful number since it is divisible by the number (13) formed by its first and last digit.

It is an amenable number.

11304002341333 is a deficient number, since it is larger than the sum of its proper divisors (869538641655).

11304002341333 is an equidigital number, since it uses as much as digits as its factorization.

11304002341333 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 869538641654.

The product of its (nonzero) digits is 7776, while the sum is 28.

Adding to 11304002341333 its reverse (33314320040311), we get a palindrome (44618322381644).

The spelling of 11304002341333 in words is "eleven trillion, three hundred four billion, two million, three hundred forty-one thousand, three hundred thirty-three".