Base | Representation |
---|---|
bin | 10000011100110011000… |
… | …100000110100000111001 |
3 | 11000001211211100001020112 |
4 | 100130303010012200321 |
5 | 122010111334041441 |
6 | 2223151440434105 |
7 | 144446120624645 |
oct | 20346304064071 |
9 | 4001754301215 |
10 | 1130433112121 |
11 | 3a6461026625 |
12 | 163103918935 |
13 | 827a3b06321 |
14 | 3c9db255c25 |
15 | 1e61262e4eb |
hex | 10733106839 |
1130433112121 has 16 divisors (see below), whose sum is σ = 1162246262784. Its totient is φ = 1098951298704.
The previous prime is 1130433112117. The next prime is 1130433112189. The reversal of 1130433112121 is 1212113340311.
It is a cyclic number.
It is not a de Polignac number, because 1130433112121 - 22 = 1130433112117 is a prime.
It is a super-3 number, since 3×11304331121213 (a number of 37 digits) contains 333 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (1130433114121) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 13341536 + ... + 13425998.
It is an arithmetic number, because the mean of its divisors is an integer number (72640391424).
Almost surely, 21130433112121 is an apocalyptic number.
It is an amenable number.
1130433112121 is a deficient number, since it is larger than the sum of its proper divisors (31813150663).
1130433112121 is a wasteful number, since it uses less digits than its factorization.
1130433112121 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 86420.
The product of its (nonzero) digits is 432, while the sum is 23.
Adding to 1130433112121 its reverse (1212113340311), we get a palindrome (2342546452432).
The spelling of 1130433112121 in words is "one trillion, one hundred thirty billion, four hundred thirty-three million, one hundred twelve thousand, one hundred twenty-one".
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