113044122120101 has 4 divisors (see below), whose sum is σ = 113046317757312. Its totient is φ = 113041926482892.

The previous prime is 113044122120077. The next prime is 113044122120113. The reversal of 113044122120101 is 101021221440311.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-113044122120101 is a prime.

It is a super-3 number, since 3×113044122120101³ (a number of 43 digits) contains 333 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (113044122120131) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1097741375 + ... + 1097844348.

It is an arithmetic number, because the mean of its divisors is an integer number (28261579439328).

Almost surely, 2^{113044122120101} is an apocalyptic number.

It is an amenable number.

113044122120101 is a deficient number, since it is larger than the sum of its proper divisors (2195637211).

113044122120101 is an equidigital number, since it uses as much as digits as its factorization.

113044122120101 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2195637210.

The product of its (nonzero) digits is 384, while the sum is 23.

Adding to 113044122120101 its reverse (101021221440311), we get a palindrome (214065343560412).

The spelling of 113044122120101 in words is "one hundred thirteen trillion, forty-four billion, one hundred twenty-two million, one hundred twenty thousand, one hundred one".