11304425131 has 8 divisors (see below), whose sum is σ = 11554513920. Its totient is φ = 11057011368.

The previous prime is 11304425107. The next prime is 11304425137. The reversal of 11304425131 is 13152440311.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 11304425131 - 2¹⁷ = 11304294059 is a prime.

It is a super-3 number, since 3×11304425131³ (a number of 31 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 11304425096 and 11304425105.

It is not an unprimeable number, because it can be changed into a prime (11304425137) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 660211 + ... + 677116.

It is an arithmetic number, because the mean of its divisors is an integer number (1444314240).

Almost surely, 2^11304425131 is an apocalyptic number.

11304425131 is a deficient number, since it is larger than the sum of its proper divisors (250088789).

11304425131 is a wasteful number, since it uses less digits than its factorization.

11304425131 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1337513.

The product of its (nonzero) digits is 1440, while the sum is 25.

Adding to 11304425131 its reverse (13152440311), we get a palindrome (24456865442).

The spelling of 11304425131 in words is "eleven billion, three hundred four million, four hundred twenty-five thousand, one hundred thirty-one".