11304430133 has 4 divisors (see below), whose sum is σ = 11899400160. Its totient is φ = 10709460108.

The previous prime is 11304430127. The next prime is 11304430201. The reversal of 11304430133 is 33103440311.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 33103440311 = 138163 ⋅239597.

It is a cyclic number.

It is not a de Polignac number, because 11304430133 - 2¹⁰ = 11304429109 is a prime.

It is a super-3 number, since 3×11304430133³ (a number of 31 digits) contains 333 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 11304430099 and 11304430108.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11304430633) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 297484985 + ... + 297485022.

It is an arithmetic number, because the mean of its divisors is an integer number (2974850040).

Almost surely, 2^11304430133 is an apocalyptic number.

It is an amenable number.

11304430133 is a deficient number, since it is larger than the sum of its proper divisors (594970027).

11304430133 is an equidigital number, since it uses as much as digits as its factorization.

11304430133 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 594970026.

The product of its (nonzero) digits is 1296, while the sum is 23.

Adding to 11304430133 its reverse (33103440311), we get a palindrome (44407870444).

The spelling of 11304430133 in words is "eleven billion, three hundred four million, four hundred thirty thousand, one hundred thirty-three".