Base | Representation |
---|---|
bin | 1010010010000010011100… |
… | …1111111100101010101001 |
3 | 1111000202012202022202222220 |
4 | 2210200213033330222221 |
5 | 2440210131134241040 |
6 | 40013241230104253 |
7 | 2244521514012141 |
oct | 244404717745251 |
9 | 44022182282886 |
10 | 11305012415145 |
11 | 3669479872969 |
12 | 1326ba194b089 |
13 | 64009a83a487 |
14 | 2b124628b921 |
15 | 149108e232d0 |
hex | a48273fcaa9 |
11305012415145 has 32 divisors (see below), whose sum is σ = 18593882499072. Its totient is φ = 5861017274112.
The previous prime is 11305012415143. The next prime is 11305012415171. The reversal of 11305012415145 is 54151421050311.
11305012415145 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 11305012415145 - 21 = 11305012415143 is a prime.
It is not an unprimeable number, because it can be changed into a prime (11305012415143) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 8711497 + ... + 9924726.
It is an arithmetic number, because the mean of its divisors is an integer number (581058828096).
Almost surely, 211305012415145 is an apocalyptic number.
11305012415145 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
It is an amenable number.
11305012415145 is a deficient number, since it is larger than the sum of its proper divisors (7288870083927).
11305012415145 is a wasteful number, since it uses less digits than its factorization.
11305012415145 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 18637361.
The product of its (nonzero) digits is 12000, while the sum is 33.
Adding to 11305012415145 its reverse (54151421050311), we get a palindrome (65456433465456).
The spelling of 11305012415145 in words is "eleven trillion, three hundred five billion, twelve million, four hundred fifteen thousand, one hundred forty-five".
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