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11307056503 = 19595108237
BaseRepresentation
bin10101000011111001…
…11111110101110111
31002012000012222120111
422201330333311313
5141124101302003
65105553243451
7550125252211
oct124174776567
932160188514
1011307056503
1148825a19a6
122236863587
1310b27262a2
1479399d5b1
154629e3e6d
hex2a1f3fd77

11307056503 has 4 divisors (see below), whose sum is σ = 11902164760. Its totient is φ = 10711948248.

The previous prime is 11307056491. The next prime is 11307056513. The reversal of 11307056503 is 30565070311.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-11307056503 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11307056513) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 297554100 + ... + 297554137.

It is an arithmetic number, because the mean of its divisors is an integer number (2975541190).

Almost surely, 211307056503 is an apocalyptic number.

11307056503 is a deficient number, since it is larger than the sum of its proper divisors (595108257).

11307056503 is an equidigital number, since it uses as much as digits as its factorization.

11307056503 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 595108256.

The product of its (nonzero) digits is 9450, while the sum is 31.

The spelling of 11307056503 in words is "eleven billion, three hundred seven million, fifty-six thousand, five hundred three".

Divisors: 1 19 595108237 11307056503