Base | Representation |
---|---|
bin | 10000011101010100110… |
… | …111011010001110010010 |
3 | 11000010022100102121201121 |
4 | 100131110313122032102 |
5 | 122012242023212242 |
6 | 2223324015352454 |
7 | 144466145111323 |
oct | 20352467321622 |
9 | 4003270377647 |
10 | 1131000210322 |
11 | 3a6722151924 |
12 | 16324182272a |
13 | 828644521a8 |
14 | 3ca526b644a |
15 | 1e6472ed667 |
hex | 10754dda392 |
1131000210322 has 4 divisors (see below), whose sum is σ = 1696500315486. Its totient is φ = 565500105160.
The previous prime is 1131000210299. The next prime is 1131000210323. The reversal of 1131000210322 is 2230120001311.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 1081373291881 + 49626918441 = 1039891^2 + 222771^2 .
It is a super-2 number, since 2×11310002103222 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 1131000210296 and 1131000210305.
It is not an unprimeable number, because it can be changed into a prime (1131000210323) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 282750052579 + ... + 282750052582.
Almost surely, 21131000210322 is an apocalyptic number.
1131000210322 is a deficient number, since it is larger than the sum of its proper divisors (565500105164).
1131000210322 is an equidigital number, since it uses as much as digits as its factorization.
1131000210322 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 565500105163.
The product of its (nonzero) digits is 72, while the sum is 16.
Adding to 1131000210322 its reverse (2230120001311), we get a palindrome (3361120211633).
The spelling of 1131000210322 in words is "one trillion, one hundred thirty-one billion, two hundred ten thousand, three hundred twenty-two".
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