Base | Representation |
---|---|
bin | 110100101010101001… |
… | …0101100010001111111 |
3 | 101210221010211000221221 |
4 | 1221111102230101333 |
5 | 3323112112104043 |
6 | 123542451534211 |
7 | 11112504045562 |
oct | 1512522542177 |
9 | 353833730857 |
10 | 113100113023 |
11 | 43a69079997 |
12 | 19b04bba367 |
13 | a885864501 |
14 | 568cc0a4d9 |
15 | 2e1e3648ed |
hex | 1a554ac47f |
113100113023 has 4 divisors (see below), whose sum is σ = 113636132728. Its totient is φ = 112564093320.
The previous prime is 113100113003. The next prime is 113100113057. The reversal of 113100113023 is 320311001311.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-113100113023 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 113100112988 and 113100113006.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (113100113003) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 268009536 + ... + 268009957.
It is an arithmetic number, because the mean of its divisors is an integer number (28409033182).
Almost surely, 2113100113023 is an apocalyptic number.
113100113023 is a deficient number, since it is larger than the sum of its proper divisors (536019705).
113100113023 is an equidigital number, since it uses as much as digits as its factorization.
113100113023 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 536019704.
The product of its (nonzero) digits is 54, while the sum is 16.
Adding to 113100113023 its reverse (320311001311), we get a palindrome (433411114334).
The spelling of 113100113023 in words is "one hundred thirteen billion, one hundred million, one hundred thirteen thousand, twenty-three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.090 sec. • engine limits •