1131001200133 has 4 divisors (see below), whose sum is σ = 1292572800160. Its totient is φ = 969429600108.

The previous prime is 1131001200101. The next prime is 1131001200149. The reversal of 1131001200133 is 3310021001311.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1131001200133 - 2⁵ = 1131001200101 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1131001200233) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 80785800003 + ... + 80785800016.

It is an arithmetic number, because the mean of its divisors is an integer number (323143200040).

Almost surely, 2^{1131001200133} is an apocalyptic number.

It is an amenable number.

1131001200133 is a deficient number, since it is larger than the sum of its proper divisors (161571600027).

1131001200133 is an equidigital number, since it uses as much as digits as its factorization.

1131001200133 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 161571600026.

The product of its (nonzero) digits is 54, while the sum is 16.

Adding to 1131001200133 its reverse (3310021001311), we get a palindrome (4441022201444).

The spelling of 1131001200133 in words is "one trillion, one hundred thirty-one billion, one million, two hundred thousand, one hundred thirty-three".