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113100121 = 313648391
BaseRepresentation
bin1101011110111…
…00010101011001
321212211002012101
412233130111121
5212423200441
615120043401
72542222651
oct657342531
9255732171
10113100121
1158929882
1231a63561
131a57c464
1411041361
159de1231
hex6bdc559

113100121 has 4 divisors (see below), whose sum is σ = 116748544. Its totient is φ = 109451700.

The previous prime is 113100107. The next prime is 113100149. The reversal of 113100121 is 121001311.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 113100121 - 217 = 112969049 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 113100098 and 113100107.

It is not an unprimeable number, because it can be changed into a prime (113100151) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1824165 + ... + 1824226.

It is an arithmetic number, because the mean of its divisors is an integer number (29187136).

Almost surely, 2113100121 is an apocalyptic number.

It is an amenable number.

113100121 is a deficient number, since it is larger than the sum of its proper divisors (3648423).

113100121 is an equidigital number, since it uses as much as digits as its factorization.

113100121 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3648422.

The product of its (nonzero) digits is 6, while the sum is 10.

The square root of 113100121 is about 10634.8540657594. The cubic root of 113100121 is about 483.6015563423.

Adding to 113100121 its reverse (121001311), we get a palindrome (234101432).

The spelling of 113100121 in words is "one hundred thirteen million, one hundred thousand, one hundred twenty-one".

Divisors: 1 31 3648391 113100121