113100121133101 has 4 divisors (see below), whose sum is σ = 113100316005600. Its totient is φ = 113099926260604.

The previous prime is 113100121132879. The next prime is 113100121133117. The reversal of 113100121133101 is 101331121001311.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 113100121133101 - 2⁴⁵ = 77915749044269 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (113100121133141) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 96563071 + ... + 97727308.

It is an arithmetic number, because the mean of its divisors is an integer number (28275079001400).

Almost surely, 2^{113100121133101} is an apocalyptic number.

It is an amenable number.

113100121133101 is a deficient number, since it is larger than the sum of its proper divisors (194872499).

113100121133101 is an equidigital number, since it uses as much as digits as its factorization.

113100121133101 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 194872498.

The product of its (nonzero) digits is 54, while the sum is 19.

Adding to 113100121133101 its reverse (101331121001311), we get a palindrome (214431242134412).

The spelling of 113100121133101 in words is "one hundred thirteen trillion, one hundred billion, one hundred twenty-one million, one hundred thirty-three thousand, one hundred one".