Base | Representation |
---|---|
bin | 11001101101110101100000… |
… | …111011100001000010011011 |
3 | 112211110100110011011200112020 |
4 | 121231311200323201002123 |
5 | 104311021322001120443 |
6 | 1040313514312145523 |
7 | 32552164134006003 |
oct | 3155654073410233 |
9 | 484410404150466 |
10 | 113101000020123 |
11 | 33045956a79985 |
12 | 108278940982a3 |
13 | 4b154bc85717b |
14 | 1dd0190a0d003 |
15 | d1203ad78583 |
hex | 66dd60ee109b |
113101000020123 has 8 divisors (see below), whose sum is σ = 150804844377168. Its totient is φ = 75398911171584.
The previous prime is 113101000020091. The next prime is 113101000020131. The reversal of 113101000020123 is 321020000101311.
It is a happy number.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 113101000020123 - 25 = 113101000020091 is a prime.
It is not an unprimeable number, because it can be changed into a prime (113101000020133) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 438726790 + ... + 438984507.
It is an arithmetic number, because the mean of its divisors is an integer number (18850605547146).
Almost surely, 2113101000020123 is an apocalyptic number.
113101000020123 is a deficient number, since it is larger than the sum of its proper divisors (37703844357045).
113101000020123 is an equidigital number, since it uses as much as digits as its factorization.
113101000020123 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 877754253.
The product of its (nonzero) digits is 36, while the sum is 15.
Adding to 113101000020123 its reverse (321020000101311), we get a palindrome (434121000121434).
The spelling of 113101000020123 in words is "one hundred thirteen trillion, one hundred one billion, twenty thousand, one hundred twenty-three".
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