Base | Representation |
---|---|
bin | 110100101010101011… |
… | …0001001101101111111 |
3 | 101210221012112010010211 |
4 | 1221111112021231333 |
5 | 3323112330120111 |
6 | 123542523213251 |
7 | 11112514544116 |
oct | 1512526115577 |
9 | 353835463124 |
10 | 113101020031 |
11 | 43a6963938a |
12 | 19b05377227 |
13 | a885ac12bc |
14 | 568cda4c7d |
15 | 2e1e493521 |
hex | 1a55589b7f |
113101020031 has 4 divisors (see below), whose sum is σ = 116749440064. Its totient is φ = 109452600000.
The previous prime is 113101020029. The next prime is 113101020037. The reversal of 113101020031 is 130020101311.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 113101020031 - 21 = 113101020029 is a prime.
It is a super-2 number, since 2×1131010200312 (a number of 23 digits) contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 113101019993 and 113101020020.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (113101020037) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1824209970 + ... + 1824210031.
It is an arithmetic number, because the mean of its divisors is an integer number (29187360016).
Almost surely, 2113101020031 is an apocalyptic number.
113101020031 is a deficient number, since it is larger than the sum of its proper divisors (3648420033).
113101020031 is an equidigital number, since it uses as much as digits as its factorization.
113101020031 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3648420032.
The product of its (nonzero) digits is 18, while the sum is 13.
Adding to 113101020031 its reverse (130020101311), we get a palindrome (243121121342).
The spelling of 113101020031 in words is "one hundred thirteen billion, one hundred one million, twenty thousand, thirty-one".
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