Search a number
-
+
1131010220143 = 1765036407881
BaseRepresentation
bin10000011101010101011…
…101100110000001101111
311000010100001021011121201
4100131111131212001233
5122012302104021033
62223325014110331
7144466326151426
oct20352535460157
94003301234551
101131010220143
113a6727869401
1216324504b3a7
138286654836b
143ca53b602bd
151e64812947d
hex1075576606f

1131010220143 has 4 divisors (see below), whose sum is σ = 1131016804528. Its totient is φ = 1131003635760.

The previous prime is 1131010220117. The next prime is 1131010220149. The reversal of 1131010220143 is 3410220101311.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1131010220143 - 237 = 993571266671 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 1131010220143.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1131010220149) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3027438 + ... + 3380443.

It is an arithmetic number, because the mean of its divisors is an integer number (282754201132).

Almost surely, 21131010220143 is an apocalyptic number.

1131010220143 is a deficient number, since it is larger than the sum of its proper divisors (6584385).

1131010220143 is an equidigital number, since it uses as much as digits as its factorization.

1131010220143 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 6584384.

The product of its (nonzero) digits is 144, while the sum is 19.

Adding to 1131010220143 its reverse (3410220101311), we get a palindrome (4541230321454).

The spelling of 1131010220143 in words is "one trillion, one hundred thirty-one billion, ten million, two hundred twenty thousand, one hundred forty-three".

Divisors: 1 176503 6407881 1131010220143