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1131010424323 = 1387000801871
BaseRepresentation
bin10000011101010101011…
…110010111111000000011
311000010100001122112200221
4100131111132113320003
5122012302132034243
62223325022323511
7144466330661623
oct20352536277003
94003301575627
101131010424323
113a672799884a
12163245129597
13828665ba290
143ca53bb4883
151e648169bed
hex10755797e03

1131010424323 has 4 divisors (see below), whose sum is σ = 1218011226208. Its totient is φ = 1044009622440.

The previous prime is 1131010424287. The next prime is 1131010424351. The reversal of 1131010424323 is 3234240101311.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1131010424323 - 29 = 1131010423811 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1131010424353) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 43500400923 + ... + 43500400948.

It is an arithmetic number, because the mean of its divisors is an integer number (304502806552).

Almost surely, 21131010424323 is an apocalyptic number.

1131010424323 is a gapful number since it is divisible by the number (13) formed by its first and last digit.

1131010424323 is a deficient number, since it is larger than the sum of its proper divisors (87000801885).

1131010424323 is an equidigital number, since it uses as much as digits as its factorization.

1131010424323 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 87000801884.

The product of its (nonzero) digits is 1728, while the sum is 25.

Adding to 1131010424323 its reverse (3234240101311), we get a palindrome (4365250525634).

The spelling of 1131010424323 in words is "one trillion, one hundred thirty-one billion, ten million, four hundred twenty-four thousand, three hundred twenty-three".

Divisors: 1 13 87000801871 1131010424323