11310113110031 has 4 divisors (see below), whose sum is σ = 11310123380952. Its totient is φ = 11310102839112.

The previous prime is 11310113109991. The next prime is 11310113110033. The reversal of 11310113110031 is 13001131101311.

It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length.

It is a cyclic number.

It is not a de Polignac number, because 11310113110031 - 2²² = 11310108915727 is a prime.

It is a super-2 number, since 2×11310113110031² (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 11310113109991 and 11310113110009.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11310113110033) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3253901 + ... + 5762646.

It is an arithmetic number, because the mean of its divisors is an integer number (2827530845238).

Almost surely, 2^{11310113110031} is an apocalyptic number.

11310113110031 is a deficient number, since it is larger than the sum of its proper divisors (10270921).

11310113110031 is an equidigital number, since it uses as much as digits as its factorization.

11310113110031 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 10270920.

The product of its (nonzero) digits is 27, while the sum is 17.

Adding to 11310113110031 its reverse (13001131101311), we get a palindrome (24311244211342).

The spelling of 11310113110031 in words is "eleven trillion, three hundred ten billion, one hundred thirteen million, one hundred ten thousand, thirty-one".