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1131012515551 = 4127585671111
BaseRepresentation
bin10000011101010101100…
…110010110011011011111
311000010100012120210022211
4100131111212112123133
5122012303200444201
62223325135221251
7144466354521532
oct20352546263337
94003305523284
101131012515551
113a6729096a36
12163245977827
1382866b700a9
143ca5419aa19
151e64842e651
hex107559966df

1131012515551 has 4 divisors (see below), whose sum is σ = 1158598186704. Its totient is φ = 1103426844400.

The previous prime is 1131012515543. The next prime is 1131012515587. The reversal of 1131012515551 is 1555152101311.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1131012515551 - 23 = 1131012515543 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1131012515251) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 13792835515 + ... + 13792835596.

It is an arithmetic number, because the mean of its divisors is an integer number (289649546676).

Almost surely, 21131012515551 is an apocalyptic number.

1131012515551 is a deficient number, since it is larger than the sum of its proper divisors (27585671153).

1131012515551 is an equidigital number, since it uses as much as digits as its factorization.

1131012515551 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 27585671152.

The product of its (nonzero) digits is 3750, while the sum is 31.

Adding to 1131012515551 its reverse (1555152101311), we get a palindrome (2686164616862).

The spelling of 1131012515551 in words is "one trillion, one hundred thirty-one billion, twelve million, five hundred fifteen thousand, five hundred fifty-one".

Divisors: 1 41 27585671111 1131012515551