113101311313 has 4 divisors (see below), whose sum is σ = 115507722240. Its totient is φ = 110694900388.

The previous prime is 113101311299. The next prime is 113101311317. The reversal of 113101311313 is 313113101311.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 313113101311 = 467 ⋅670477733.

It is a cyclic number.

It is not a de Polignac number, because 113101311313 - 2¹³ = 113101303121 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (113101311317) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1203205393 + ... + 1203205486.

It is an arithmetic number, because the mean of its divisors is an integer number (28876930560).

Almost surely, 2^113101311313 is an apocalyptic number.

It is an amenable number.

113101311313 is a deficient number, since it is larger than the sum of its proper divisors (2406410927).

113101311313 is an equidigital number, since it uses as much as digits as its factorization.

113101311313 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2406410926.

The product of its (nonzero) digits is 81, while the sum is 19.

Adding to 113101311313 its reverse (313113101311), we get a palindrome (426214412624).

The spelling of 113101311313 in words is "one hundred thirteen billion, one hundred one million, three hundred eleven thousand, three hundred thirteen".